What is the Inverse Laplace Transform of (9s+5)/(s2-9) with s>3?

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Homework Statement


Find the inverse Laplace Transform of (9s+5)/(s2-9) given s>3


Homework Equations


I have a table of Laplace Transforms.
it says "sinh at" goes with a/(s2-a2) and "cosh at" goes with s/(s2-a2)


The Attempt at a Solution


I know how to split it up and find the inverse Laplace Transform but I don't know what it means by "cosh". I assume it is some variation of cosine? Someone said it means degrees but I don't see how that would change the problem.
 
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cosh(x) = 1/2 [exp(x) + exp(-x)]


sinh(x) = 1/2 [exp(x) - exp(-x)]
 
thanks, apparently the professor somewhat explained this but I missed it.
 
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