What is the Laplace transform of a step function?

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Discussion Overview

The discussion revolves around finding the Laplace transform of a step function defined piecewise, specifically for the function $\displaystyle f(t)=1$ for $\displaystyle 1\le t\le 4$ and $\displaystyle f(t)=0$ otherwise. The conversation includes considerations of how the transform might change if the endpoints of the interval are adjusted.

Discussion Character

  • Mathematical reasoning

Main Points Raised

  • One participant presents the Laplace transform using the definition, stating that the integral is taken from 1 to 4.
  • Another participant questions how the answer would differ if one or both endpoints were excluded from the definition of the function.
  • A response indicates that excluding endpoints would not change the value of the integral, as altering a function at countably many points does not affect the integral's value.

Areas of Agreement / Disagreement

Participants generally agree that changing the definition of the function at specific points does not alter the integral, but the discussion does not reach a consensus on the implications of endpoint exclusions in all contexts.

Contextual Notes

The discussion assumes familiarity with the properties of integrals and the definition of the Laplace transform, but does not explore the implications of these properties in detail.

alexmahone
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Find the Laplace transform of $\displaystyle f(t)=1$ if $\displaystyle 1\le t\le 4$; $\displaystyle f(t)=0$ if $\displaystyle t<1$ or if $\displaystyle t>4$.
 
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Alexmahone said:
Find the Laplace transform of $\displaystyle f(t)=1$ if $\displaystyle 1\le t\le 4$; $\displaystyle f(t)=0$ if $\displaystyle t<1$ or if $\displaystyle t>4$.

Straight forward application of the definition:

\[ F(s)=\int_0^{\infty}f(t)e^{-st}\; dt=\int_1^4e^{-st}\;dt \]

CB
 
CaptainBlack said:
Straight forward application of the definition:

\[ F(s)=\int_0^{\infty}f(t)e^{-st}\; dt=\int_1^4e^{-st}\;dt \]

CB

Thanks. How would the answer differ if one of the endpoints 1 or 4 (or both) were excluded?
 
Alexmahone said:
Thanks. How would the answer differ if one of the endpoints 1 or 4 (or both) were excluded?

Do you mean if your function were defined as, for example, $f(t)=1$ if $1<t\le 4$; $f(t)=0$ if $t\le 1$ or if $t>4$? It would make no difference. The reason is that the changing of one point in a function does not alter the integral of that function. In fact, changing the function at countably many points does not change the value of the integral.
 
Ackbach said:
Do you mean if your function were defined as, for example, $f(t)=1$ if $1<t\le 4$; $f(t)=0$ if $t\le 1$ or if $t>4$? It would make no difference. The reason is that the changing of one point in a function does not alter the integral of that function. In fact, changing the function at countably many points does not change the value of the integral.

That's exactly what I meant. Thanks.
 
Alexmahone said:
That's exactly what I meant. Thanks.

You're welcome, as always!
 

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