What is the laplace transform of t(sinh(3t))?

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SUMMARY

The Laplace transform of the function t(sinh(3t)) can be computed using the definition of the hyperbolic sine function, sinh(3t) = 1/2 (e^(3t) - e^(-3t)). The Laplace transform of t is given by 1/s^2. By multiplying t with the definition of sinh(3t) and applying the Laplace transform to each term separately, the result is 1/2 * (1/(s-3)^2 - 1/(s+3)^2). This method is confirmed as correct, leading to a successful outcome for the student who achieved a 99% on their final exam.

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Homework Statement


So I finally had my final today, and I was so worried because I needed a 90% at least to pass the class with an A. :\ So I'm really worried with a few of my answers.

One of those (that I can remember) was the laplace transform of: t(sinh(3t).

Homework Equations



laplace t = 1/s^2
Definition of: sinh(3t) = 1/2 (e^3t - e^-3t), I think.

The Attempt at a Solution



So I had no idea how to do this, since it wasn't in the table. XD What I did was multiply t by 1/2 (e^3x-e^-3x), then used the laplace of each one separately. Something like:

1/2* (1/(s-3)^2 - 1/(s+3)^2, or something like that. Was this the correct way to do this?
 
Last edited:
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Omg as I typed that last post I received my grade for the final by email. I got a 99%. :D I'm so excited woooo. :D :D :D That was so fast we just did the final this morning...
 

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