What is the lattice energy of LiI? Given the information below.

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SUMMARY

The lattice energy of lithium iodide (LiI) can be calculated using the provided thermodynamic values. The heat of formation for LiI is -270 kJ/mol, while the heat of sublimation for lithium (Li) is 159.40 kJ/mol and for iodine (I2) is 48.30 kJ/mol. The ionization energy for Li is 520 kJ/mol, and the bond dissociation energy for I2 is 149 kJ/mol. The electron affinity for iodine is -295 kJ/mol. These values are essential for determining the lattice energy through the Born-Haber cycle.

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  • Understanding of lattice energy concepts
  • Familiarity with the Born-Haber cycle
  • Knowledge of thermodynamic properties such as heat of formation and sublimation
  • Basic skills in energy calculations and unit conversions
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  • Study the Born-Haber cycle for ionic compounds
  • Learn how to calculate lattice energy using the Born-Haber cycle
  • Explore thermodynamic properties of other ionic compounds
  • Investigate the relationship between lattice energy and ionic size
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Homework Statement



What is the lattice energy of LiI? Given the information below.

Heat of formation for LiI = -270 kJ/mol

Heat of sublimation for Li = 159.40 kJ/mol

Ionization energy for Li = 520 kJ/mol

Bond dissociation energy for I2 = 149 kJ/mol

Electron affinity for I = - 295 kJ/mol

Heat of sublimation for I2 = 48.30 kJ/mol

Homework Equations





The Attempt at a Solution



Could someone give me a hint?
 
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This should help tremendously:

Code:
http://answers.yahoo.com/question/index?qid=20080121195206AA88t5P
 

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