What is the limit of (1-1/n)^n as n approaches infinity?

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SUMMARY

The limit of (1-1/n)^n as n approaches infinity is e^-1, which equals approximately 0.367879. This conclusion is derived from the general limit property lim n goes to infinity (1+x/n)^n = e^x, where x is -1 in this case. Understanding this limit requires familiarity with the definition of the mathematical constant e and its properties in calculus.

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  • Study the derivation of the limit lim n goes to infinity (1+x/n)^n = e^x
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Homework Statement



give the limit if it exist of (1-1/n)^n n=1 to infinity

the teacher wrote:
lim n goes to infinity (1+x/n)^n = e^x

so therefore
lim n goes to infinity (1-1/n)^n = e^-1

can someone explain this to me.
 
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how I'm i suppose to know that

(1+x/n)^n = e^x ??
 
intenzxboi said:
how I'm i suppose to know that

(1+x/n)^n = e^x ??

What is your definition of "e"?
 

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