What is the limit of [2x^{2}y/(x^4 + y^4)] as (x,y) approaches (0,0)?

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SUMMARY

The limit of the function 2x²y/(x⁴ + y⁴) as (x,y) approaches (0,0) does not exist. Evaluations along the x-axis, y-axis, and lines of the form y=mx all yield a limit of 0, leading to the misconception that the limit exists. However, testing along the curve x=y reveals that the limit approaches infinity, confirming that the overall limit is undefined. This highlights the necessity of considering multiple paths in multivariable limits.

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Homework Statement


Find the limit, if it exists, or show that the limit does not exist.
lim_{(x,y)->(0,0)}[2x^{2}y/(x^4 + y^4)]

Homework Equations



The Attempt at a Solution


Along the y-axis and the x-axis, the limit approaches 0. Along y = mx, the limit also appaches 0. So, it appears that the limit is 0. However, the answer is that the limit "does not exist."

Should I just keep making new equations until I find where the limit does not = 0? I even tried the Squeeze Theorem...

0<[2x^{2}y/(x^4 + y^4)]<2x^2
because y/(x^4 + y^4)<1
so as x -> 0, the whole function -> 0 right?

Why doesn't that work to prove that the limit would be 0?
 
Last edited:
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Along x=y, the limit becomes

\lim _{x \to 0} \frac {2x^3}{2x^4} = \lim _{x \to 0} \frac 1x
 
Thanks, I got it!
 
Did you read my response to your first question? No matter how many curves you try you can never prove that a limit exists that way. In fact, it is possible to show that the limit is the same for all straight lines through the origin, that would still not show that the limit is the same for curved lines.
 

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