MHB What is the limit of a complex fraction with L'Hopital's rule?

  • Thread starter Thread starter karush
  • Start date Start date
karush
Gold Member
MHB
Messages
3,240
Reaction score
5
\tiny{s8.1.6.64}
Evaluate
$\displaystyle\lim_{x \to 2}
\dfrac{\sqrt{6-x}{-2}}{\sqrt{3-x}-1}$

ok so if you plug in 2 directly you get $\dfrac{0}{0}$

So we either use L'H rule or use conjugate

or is there better way
 
Physics news on Phys.org
L'Hopital works

you can also multiply numerator and denominator by both conjugates
 
Last edited by a moderator:

Similar threads

Replies
3
Views
2K
Replies
8
Views
1K
Replies
3
Views
1K
Replies
1
Views
2K
Replies
1
Views
2K
Replies
4
Views
2K
Replies
2
Views
847
Replies
4
Views
1K
Back
Top