- #1

karush

Gold Member

MHB

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Find the average value of the function on the given interval. $\sqrt{x}\quad [0,4]$

**average value**$\boxed{f_{ave}=\dfrac{1}{b-a}\int_a^b f(x) \ dx}$

**so with**$a=0$ and $b=4$ thus

$\dfrac{1}{4-0}\displaystyle\int_0^4 \sqrt{x} \ dx

\implies =\dfrac{1}{4}\left[\dfrac{2}{3}x^{\dfrac{3}{2}}\right]^4_0

\implies = \dfrac{1}{4}\dfrac{16}{3}=\dfrac{4}{3}$

ok, I think this is correct, but possible typos

I want to poIst this problem on

i will add it in... been getting lots of views on

**IN**even tho it is not essentually a math forum

of I Suggest they come here