What is the limit of the function [sqrt(x-1)] as x approaches 1?

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The limit of the function sqrt(x-1) as x approaches 1 is undefined from the left-hand side due to the square root of a negative number. However, computational tools like Mathematica and Wolfram Alpha return a limit of 0, indicating that they consider complex values. The same reasoning applies to the limit of sqrt(1-x) as x approaches 1, where the right-hand limit is also undefined, yet these tools provide a limit of 0. The consensus is that for assignments, the correct answer is to submit 'undefined' based on the real number context.

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limit x-->1 of [sqrt(x-1)]

i know that for limit to be defined the left and right handed limits should be equal.
in the above problem, the left handed limit is undefined because it is the square rot of a negative no. but i checked this question on alphawolfram.com and also on MATHEMATICA . both the programs were giving limit as 0
so i supposed i was missing something but when i submitted my answer as 'undefined' it was marked as correct and i was given full credit
so please everyone clarify this problem
and also consider this one: lim x-->1 of sqrt[1-x]
in this case the right hand liit is not defined but again mathematica gave the same answer '0'
 
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khurram usman said:
i know that for limit to be defined the left and right handed limits should be equal.
in the above problem, the left handed limit is undefined because it is the square rot of a negative no. but i checked this question on alphawolfram.com and also on MATHEMATICA . both the programs were giving limit as 0
so i supposed i was missing something but when i submitted my answer as 'undefined' it was marked as correct and i was given full credit
so please everyone clarify this problem
and also consider this one: lim x-->1 of sqrt[1-x]
in this case the right hand liit is not defined but again mathematica gave the same answer '0'
You are correct in saying that for f:\mathbb{R}^+\mapsto\mathbb{R}^+, f:x\mapsto\sqrt{x}, the left-hand limit does not exist. However, Mathematica and Wolfram Alpha (and Maple, I would imagine as well as most CAS) will quite happily work in the complex plane, where the limit does exist and is indeed zero.
 
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yes you are right there.
on the graph one of the lines was marked as real and other as imaginary.
so it means as far as i have learned, my answer was correct. the limit for both the functions is un defined
 


khurram usman said:
so it means as far as i have learned, my answer was correct. the limit for both the functions is un defined
Both functions, there is only one function: the square root. The two lines on the graph indicate the values of the function (both the real and imaginary parts).
 


ok...but i have not been taught any complex valued functions yet.
so as far as my assingnment is concernerd i should submit this as undefined.
thanks a lot
 


khurram usman said:
so as far as my assingnment is concernerd i should submit this as undefined.
It would seem so, yes.
khurram usman said:
thanks a lot
No problem.
 

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