What is the Limiting Reactant in this HCl and Mg Reaction?

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SUMMARY

The discussion focuses on determining the limiting reactant in the reaction between hydrochloric acid (HCl) and magnesium (Mg). The balanced chemical equation is Mg + 2HCl → H2 + MgCl2. Participants calculated the moles of HCl in a 25 mL solution at a concentration of 1M, yielding 0.025 moles of HCl. By weighing 0.15g, 0.3g, and 0.6g of Mg, users were guided to compute the moles of Mg and identify the limiting reactant based on the stoichiometric ratio of 2:1 for HCl to Mg.

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Homework Statement


Procedure
1. Add 25 mL of HCL solution to each flask.
2. Weigh out 0.15g, 0.3g, and 0.6g of Mg ribbon and place each sample into its own balloon




Homework Equations



Mg + 2HCl --> H2 + MgCl2

The Attempt at a Solution



show the calculations determining the limiting reactant for each reaction.

Help on how to get the limiting reactant!

And using the limiting reactant as the starting amount, determine the amount of hydrogen gas that was produced per reaction flask:
 
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I think you need to know the molarity of HCl.
 
oh my bad 1.0moles HCL/1L or 0.1 moles HCL/100mL solution
 
Since you know the molarity of HCl to be 1M, you can compute how many moles of HCl you have at 25mL. The formula Molarity = mole/volume in Liter, or mole = Molarity x Volume in liter.
Further, based on your equation, you know you need a 2 HCL to 1 Mg ratio.
So just figure out how many moles of Mg you have at .15g, .3 and .6
From that you can see your limiting reactant.
 

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