What is the Limiting Reactant in this HCl and Mg Reaction?

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Discussion Overview

The discussion revolves around identifying the limiting reactant in a chemical reaction between hydrochloric acid (HCl) and magnesium (Mg). Participants are exploring the calculations necessary to determine the limiting reactant based on the provided quantities of reactants and the stoichiometry of the reaction.

Discussion Character

  • Homework-related
  • Mathematical reasoning

Main Points Raised

  • One participant outlines a procedure involving the addition of HCl to magnesium and requests help with calculations to determine the limiting reactant.
  • Another participant suggests that knowing the molarity of HCl is essential for the calculations.
  • A subsequent post clarifies the molarity of HCl as 1.0 moles per liter, providing a specific concentration for the calculations.
  • Further, a participant explains how to compute the moles of HCl in 25 mL using the formula for molarity and emphasizes the stoichiometric ratio of 2 moles of HCl to 1 mole of Mg.
  • Participants discuss calculating the moles of Mg based on different weights (0.15g, 0.3g, and 0.6g) to identify the limiting reactant.

Areas of Agreement / Disagreement

Participants generally agree on the need to calculate the moles of HCl and Mg to determine the limiting reactant, but the discussion remains unresolved regarding the specific calculations and outcomes.

Contextual Notes

Participants have not yet provided specific calculations or resolved the question of which reactant is limiting based on the provided weights of magnesium.

yjk91
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Homework Statement


Procedure
1. Add 25 mL of HCL solution to each flask.
2. Weigh out 0.15g, 0.3g, and 0.6g of Mg ribbon and place each sample into its own balloon




Homework Equations



Mg + 2HCl --> H2 + MgCl2

The Attempt at a Solution



show the calculations determining the limiting reactant for each reaction.

Help on how to get the limiting reactant!

And using the limiting reactant as the starting amount, determine the amount of hydrogen gas that was produced per reaction flask:
 
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I think you need to know the molarity of HCl.
 
oh my bad 1.0moles HCL/1L or 0.1 moles HCL/100mL solution
 
Since you know the molarity of HCl to be 1M, you can compute how many moles of HCl you have at 25mL. The formula Molarity = mole/volume in Liter, or mole = Molarity x Volume in liter.
Further, based on your equation, you know you need a 2 HCL to 1 Mg ratio.
So just figure out how many moles of Mg you have at .15g, .3 and .6
From that you can see your limiting reactant.
 

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