What is the magnitude and direction of the second force vector in this scenario?

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Homework Help Overview

The discussion revolves around a problem involving force vectors, specifically the addition of two force vectors where one is known, and the other needs to be determined. The original poster expresses confusion regarding the direction and magnitude of the second force vector in relation to the resultant vector.

Discussion Character

  • Conceptual clarification, Assumption checking

Approaches and Questions Raised

  • Participants explore the implications of the given force vectors and question the inclusion of a northward component in the answer. There is a discussion about the interpretation of the terms used in the problem and the potential for misunderstanding the directionality of the forces involved.

Discussion Status

The conversation reflects a mix of confusion and attempts to clarify the problem. Some participants challenge the correctness of the answer provided in the answer book, while others express their understanding of the vector addition involved. There is no explicit consensus reached regarding the direction of the second force vector.

Contextual Notes

Participants note that the problem does not explicitly mention any northward direction, leading to questions about the accuracy of the answer book. The discussion also highlights the importance of understanding vector components in the context of the problem.

LuvIz4ever
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I can't figur this out!

Now i got the answer to this problem but i am so confused at this one thing... how is it that the answer is 200 N of East and 600 N of west


the question is

A force vector F1 points due east with a magnitude of 200 Newtons and a second force F2 is added to F1. The resultant of the two vectors has a magnitude of 400 Newtons and points along the East and west line. Find the magnitude and direction of F2 note that there are 2 answers.


My question is I know the answers 2oo east and 6oo west but why north of east or north of west.
 
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LuvIz4ever said:
how is it that the answer is 200 N of East and 600 N of west
I suspect that the N stands for Newtons, not north.
 
Thanks But...

Actually in the answer book it tells me it is North... I think it is weird though because of the fact that it has nothing about North.. in the question
 
The answer in your book must be wrong. You have an initial vector pointing along the east-west line. If you add to it a vector with any component at all in the north-south direction, the resultant cannot possibly be entirely along the east-west line. I suspect the Doc is absolutely right.
 
... I figured that... thanks! sooooo! Much!
 
simply put, there is 200 going "right" and 600 going "left" add 200 + (-600) leads to a net of 400, and this 400 is along EW or as most would say x-axis..

yw
 

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