JeSs_W said:The Attempt at a Solution
F = (95kg)/(3-0sec/15-0sec)[/B] = 19 N
Judging from your final value, what you actually did was F = (95kg)*(3-0m/sec/15-0sec) , which is correct.JeSs_W said:F = (95kg)/(3-0sec/15-0sec) = 19 N
The average force is the total force exerted on an object over a certain period of time, divided by the duration of that time period.
To calculate the magnitude of the average force, you would divide the total force by the time interval over which it was applied. This can be represented mathematically as Favg = ΔF/Δt.
The SI (International System of Units) unit for average force is Newtons (N). Other commonly used units for force include pounds (lb) and kilograms (kg).
Knowing the magnitude of the average force can help us understand the motion and behavior of objects. It allows us to calculate acceleration and predict how an object will move under certain conditions.
Yes, the magnitude of the average force can change over time if the total force and/or the time interval over which it is applied changes. For example, if a force is applied with varying strength over a period of time, the magnitude of the average force will also vary.