What Is the Mass and Initial Velocity of Car 1 After Collision?

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Homework Help Overview

The problem involves a collision between two cars, where one car is initially moving and the other is stationary. The final velocities and mass of one car are provided, and the goal is to determine the mass and initial velocity of the moving car.

Discussion Character

  • Exploratory, Conceptual clarification, Problem interpretation

Approaches and Questions Raised

  • Participants discuss the application of conservation of momentum in two dimensions, questioning the setup of momentum equations and the handling of unknowns. There is an exploration of how to separate the momentum into x and y components.

Discussion Status

Some participants have provided guidance on correctly applying momentum conservation principles in both dimensions, noting that initial conditions simplify the problem. There is recognition of the need to treat momentum as a vector quantity.

Contextual Notes

Participants mention the known mass and velocity of one car, as well as the final velocity of the other car, which influences the discussion on how to approach the problem. The initial momentum in the y-direction is noted to be zero.

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Homework Statement


Two cars collide as shown. Car s1 is initially moving along the x-axis at speed v1 and car 2 is stationary. The final speed of car one is 10 m/s and goes 30 degrees north of x-axis. The mass of car 2 is 2000kg and goes 6 m/s at 44 degrees south of x-axis. What is the mass and initial velocity of car 1.

Homework Equations


P = mv

The Attempt at a Solution


Pxi = m1v1. Pxf = m1v1*cos(33) + m2v2cos(44), Pxf = m1v1*cos(33) + 12000*cos(44)

My next thought was to set the two equations equal to each other because of conservation of momentum, but that won't work because there are two unknowns. Is the Pxf equation set up correctly, and if so, is there a way in which I can eliminate a variable?
 
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You have to be careful when you set equations equal to each other. Here you have momentum conservation in two dimensions so you get two momentum conservation equations, one for the x-direction and one for the y-direction. You need to say

Px, before=Px,after

and

Py, before=Py,after

Momentum is a vector so its components in all directions need to be conserved and you can't mix x and y components together.
 
Ohhhh and since Py initial is zero and the mass/velcoity of car 2 is known as well as final v for car 1 this becomes much easier. Funny how problems become less challenging when I utilize both dimensions.
 
You call it "funny", I call it "learning." Good luck.
 

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