What is the mass of NH3 per cc in a solution of ammonia gas passed into water?

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Discussion Overview

The discussion revolves around calculating the mass of ammonia (NH3) per cubic centimeter (cc) in a solution formed by passing ammonia gas into water. Participants explore various approaches to the problem, including the use of molarity and density, while addressing the correctness of equations and assumptions involved.

Discussion Character

  • Technical explanation
  • Mathematical reasoning
  • Debate/contested

Main Points Raised

  • One participant presents a calculation using the molarity equation, claiming to derive a mass of NH3 per cc but questions their result.
  • Another participant challenges the validity of the molarity equation as presented, suggesting it is incorrect and context-dependent.
  • A participant expresses a lack of understanding regarding the specific situations where the equation might be applicable.
  • Concerns are raised about the complexity of the problem, with one participant questioning the feasibility of solving an equation with two unknowns.
  • Another participant suggests disregarding molarity and density for a simpler approach, implying that one of the provided answers is closer to an expected value.
  • A hint is provided that clarifies the distinction between molarity and the mass of NH3 in milliliters, emphasizing the need to focus on the specific measurement asked for.

Areas of Agreement / Disagreement

Participants do not reach a consensus on the correct approach to the problem, with multiple competing views on the validity of the equations and methods presented. The discussion remains unresolved regarding the correct calculation of NH3 mass per cc.

Contextual Notes

There are limitations regarding the assumptions made in the equations, the applicability of the molarity concept, and the handling of multiple unknowns in the problem. These factors contribute to the complexity and uncertainty in reaching a definitive answer.

Prashasti
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Ammonia gas is passed into water, yielding a solution of density 0.93 g/cm^3 and containing 18.6% NH3 by weight. The mass of NH3 per cc of the solution is
1) 0.17
2) 0.51
3) 0.34
4) 0.68I solved it using the molarity equation.

Molarity = 10xd/MM

where,

x - % by weight
d - density
MM - Molar mass

And then I multiplied molarity with Molar mass (17 g mol^-1) and got 172.98 as the answer, whereas the answer is 0.17.

Where did I go wrong?
 
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Prashasti said:
Molarity = 10xd/MM

Here.

First, this equation is wrong as written, second, even in the correct form it is not universal - it works only in specific situations. Do you know what they are?
 
No. I'm in high school. So, I don't know much about that. What specific situations are you talking about? .
Borek said:
Here.

First, this equation is wrong as written, second, even in the correct form it is not universal - it works only in specific situations. Do you know what they are?
 
You were given this equation without any explanation?
 
Let ##x,y## the number of moles in a cc. Writing the problem we have:
$$ \frac{17x}{17x+18y} = 0.186\times 0.93 $$
 
theodoros.mihos said:
Let ##x,y## the number of moles in a cc. Writing the problem we have:
$$ \frac{17x}{17x+18y} = 0.186\times 0.93 $$
Perfect way of overcomplicating things. How you are going to solve one equation with two unknowns?
 
Forget about molarity which doesn't enter into his simple arithmetical problem.

Even forget about the density - it's not a million miles away from 1 g/cc.

Then only one of the given answers is anywhere near anything you would expect.

Though once you have seen which it is, do the working out of the exact answer.
 
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HINT:
MOLARITY is the number of moler PER LITRE of solution. Whereas you are asked the mass of NH3 in millilitres (or cc).
 
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