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Qube

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## Homework Statement

A solution is prepared by dissolving 35.0 g of a protein in enough water to make up 1.0 L in volume. If the osmotic pressure of the solution is found to be 10.0 mm Hg at 25 C, the molar mass of the protein will be closest to:

## Homework Equations

Osmotic pressure = MRT

## The Attempt at a Solution

Pressure is expressed in atm, so 10/760 = 0.013 atm = M(0.0821)(25 + 273 K)

The molarity = 5.37 * 10^-4 moles/liter.

Now, we are given that there are 35 grams of protein per 1 liter of water in the problem.

(35g/L)/(5.37 * 10^-4 moles/liter) = molar mass of the protein, since molar mass is mass/moles.

The units being divided are (grams/liter) and (moles/liter). This equals:

Grams/liter * (liters / moles)

The liters cancel out, and we get grams / mole.

Question:

1) I'm fairly confident my work is correct and my answer is similarly correct.

2) However, if this problem were to be written, say, there are 70 grams of protein in enough water to make up 2.0 L in volume, I would have to do this, right?

(70 grams / 2 liters)/molarity of the solution? Because grams/liters divided by moles/liter is equivalent to grams/liters * liters/moles and the liters cancel out and we get grams/mole.

And if the problem were to state 70 grams / 2 liters I would be erroronus to perform 70 grams / molarity, since there are 2 LITERS of water, right? Doing this would be assuming there were only 1 liter of water.