SUMMARY
The discussion focuses on calculating the mass of an ice cube placed in 500 grams of water at 60 degrees Celsius, resulting in a final temperature of 18 degrees Celsius. The heat of fusion for water is specified as 80 cal/g. The energy lost by the water is calculated using the formula Q_{lost} = 500 g × 1 cal/g × -48°C, leading to a total heat loss of 24000 calories. The heat gained by the ice cube must account for both the heat of fusion and the subsequent temperature increase.
PREREQUISITES
- Understanding of heat transfer principles
- Knowledge of specific heat capacity (C_{water})
- Familiarity with the concept of heat of fusion
- Ability to apply the conservation of energy principle
NEXT STEPS
- Calculate the mass of the ice cube using the heat gained equation
- Explore the concept of latent heat in phase changes
- Learn about calorimetry and its applications in thermal energy calculations
- Study the specific heat capacities of different substances
USEFUL FOR
Students in physics or chemistry, educators teaching thermodynamics, and anyone interested in understanding heat transfer and phase changes in materials.