What is the mass of the ice cube?

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The discussion focuses on calculating the mass of an ice cube placed in 500 grams of water at 60 degrees Celsius, resulting in a final temperature of 18 degrees Celsius. The heat of fusion for water is specified as 80 cal/g. The energy lost by the water is calculated using the formula Q_{lost} = 500 g × 1 cal/g × -48°C, leading to a total heat loss of 24000 calories. The heat gained by the ice cube must account for both the heat of fusion and the subsequent temperature increase.

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tobyguy
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take an ice cube at 0 degrees C and place it in 500 grams of water at 60 degrees C . The final temperature is 18 degrees C . What is the mass of the ice cube? heat of fusion for water is 80 cal per g. Anyone?
 
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Q_{gained} = -Q_{lost}
You know that 500 grams of water decreases in temperature from 60 to 18 degrees celsius and that C_{water} in terms of calories is 1, so the energy lost by the 60 degrees water would be: 500\times 1 \times -48. Figure out Q_{gained}. Don't forget to add the heat of fusion for x grams of the ice-cube to your heat gained.
 
You mean subtract...From |Q_{lost}|=|Q_{gained}| he should subtract the heat consumed/used to melt and the rest is used to increase temperature of water to 18°.

Daniel.
 
Yeah by add I meant "factor in". Sorry if I was unclear.
 

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