What Is the Maximum Angle Attained by a Particle Projected from Earth?

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Homework Help Overview

The problem involves a particle projected from the Earth's surface with a specified initial speed, seeking to determine the maximum angle attained by the particle. The context includes gravitational effects and energy conservation principles.

Discussion Character

  • Exploratory, Assumption checking, Mathematical reasoning

Approaches and Questions Raised

  • Participants discuss the application of conservation of energy, questioning the correctness of equations used to relate kinetic and potential energy. There is an exploration of the relationship between altitude and angle.

Discussion Status

Some participants have provided feedback on the equations presented, suggesting corrections and clarifications regarding the use of potential energy. There appears to be ongoing exploration of the correct formulation needed to address the problem.

Contextual Notes

There are indications of potential misunderstandings regarding the definitions of angle and altitude, as well as the proper setup of energy conservation equations. The discussion reflects a need for clarity on these concepts.

harambe
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Homework Statement


A particle is projeccted from the surface of the Earth with an initial speed of 4km/s.Find the maximum angle attained by the particle.Radius of the earth=6400km and g=9.8m/s2

Homework Equations



KE1+U1=KE2+U2
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The Attempt at a Solution



So I tried to proceed by this method

1/2{mv2} - GMm/R=-GM/(R+H)

Is my equation right?

[/B]
 
Last edited:
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You have the kinetic energy and the force/mass (which is the local acceleration due to gravity) in the same equation. So yes, your equation is incorrect. You are looking for the conservation of the total energy.
 
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Oops .I had to use potential energyIs it right now
 
If you are trying to calculate the altitude above the surface of the Earth, then almost. Take another look at the RHS of your equation..
 
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harambe said:
Find the maximum angle
Angle? Altitude maybe?
As Dr Dr news mentions, you have a typo in your equation.
 
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1/2{mv2} - GMm/R=-GMm/(R+H)
Is this correct
 
That looks good.
 
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