What Is the Angle Between Velocity Vector and Trajectory at Maximum Height?

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SUMMARY

The angle between the velocity vector and the trajectory of a projectile at its maximum height is definitively 0 degrees. This conclusion is drawn from the understanding that at maximum height, the vertical component of the velocity (Vy) becomes zero while the horizontal component (Vox) remains constant. The projectile's initial velocity is given as 150 m/s, and the relevant equations include Vox = Vocosθ and Vy = Vosinθ - gt, confirming that the trajectory is horizontal at this point.

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Objection
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Homework Statement



the initial velocity of a projectile is 150 m\s .the angle between the velocity vector and the trajectory at the projectile's maximum height is
a) 90
b) 45
c) zero
d) 63.1
e) 36.9

Homework Equations



Vox= vx = Vocosθ
Vy = Vosinθ-gt
Range (R) = (vo)^2*sin(2θ)/g
Maximum Height (H) = (vo)^2*(sinθ)^2/2g

The Attempt at a Solution



http://im40.gulfup.com/43qMA.jpg

in this image we can see that the angle at the maximum height is 0 but I want to get sure ?
 
Last edited by a moderator:
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Correct.
 

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