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RaeZ
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Homework Statement
A diver jumps vertically straight up off of a platform 3 meters above the surface of a pool below. The diver hits the water and comes to rest in 0.80 seconds after traveling through 3.6 vertical meters of water. (See the diagram below). Assume the acceleration of the diver through the water is constant. The goal of this problem is to work backwards to eventually find the velocity of the diver at the instant the diver leaves the platform.
Find both the velocity with which the diver hits the water and the acceleration that the diver experienced when slowing down through the water.
Homework Equations
d=v_0t+.5at^2
v=v_0+at
v^2=v_0+2ad
The Attempt at a Solution
I have no idea how to determine the final velocity of the diver(when they hit the water) without either a known initial velocity or the distance they traveled from their max height to the water.
I drew the diagram for this and looked at previous problems but none gave as little information. I also tried to use the third equation with v_0=0 and d=3 for the fall from it's maximum height to the water, but this doesn't make sense since the displacement was more than three since they jumped upwards from 3
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