What is the maximum rate of angle change for a function?

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SUMMARY

The maximum rate of angle change for a function can be determined using the derivative of the arctangent of the first derivative, represented as (arctan(y'))'. This derivative simplifies to \(\frac{y'}{(y')^2 + 1}\). To find the greatest rate of angle change, set the derivative of this expression to zero, leading to the equation \(y''' - 2(y')^2y' + y'''(y')^2 = 0\). This discussion explores the implications of this differential equation and its solutions.

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So I have been thinking of this problem... what is the greatest rate of angle change for a function? As in, what is the point in which a function achieves its greatest rate of angle change...

Well, the angle of a function can be determined by arctan(y')

The Rate of Angle change is (arctan(y'))', which equals [itex]\frac{y'}{(y')^2 +1}[/itex]

So the greatest rate of angle change is the derivative of that set to zero, which is equal to

[itex]\frac{y''' - 2(y')^2y' + y'''(y')^2}{((y')^2 +1)} = 0[/itex]

Which , you can simplify to...

[itex]y''' - 2(y')^2y' + y'''(y')^2= 0[/itex]

Is there a way that this differential equation can be solved? (This is not for homework, this is just a general question that I would like to know the answer to)
 
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Gackhammer said:
Well, the angle of a function can be determined by arctan(y')

The Rate of Angle change is (arctan(y'))', which equals [itex]\frac{y'}{(y')^2 +1}[/itex]

So the greatest rate of angle change is the derivative of that set to zero...


Or you could use the fact that ##\frac{x}{x^2+1}## attains it's maximum at x=1.
 

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