What Is the Maximum Safe Depth for the Submarine with a 40cm Window?

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Homework Statement



A research submarine has a 40.0cm -diameter window 8.70cm thick. The manufacturer says the window can withstand forces up to 1.20×10^6N . What is the submarine's maximum safe depth?

Homework Equations



P= atmosheric pressure + ρg(depth)
Pressure = Force/crossectional area

The Attempt at a Solution



1.2*10^6N/∏(.4/2)^2= Safe pressure
9.55*10^6N/m^2=Psafe

Psafe= 1atm+ρgd=101300N+1025kg/m^3*9.8m^2
9.55*10^6kg/m^3/m^2=101300kg*m/s^2+ 1025kg/m^3*9.8m^2


I really just don't even know how to proceed figuring out this moshpit of units or even if I'm doing this right in the first place?
 
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What's the pressure inside the submarine and what is the difference with the total water pressure?
 
Inside the sub is 1 atm. And what do you mean? Difference between which values?
 
If the pressure inside is equal to the pressure outside - will there be any force on the window?