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k3N70n

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## Homework Statement

A research submarine has a 10.0 -diameter window 8.90 thick. The manufacturer says the window can withstand forces up to 1.10×10^6 . What is the submarine's maximum safe depth?

The pressure inside the submarine is maintained at 1.0 atm.

## Homework Equations

p=F/A

p=p(not) + ρgd

A=Pi*r^2

## The Attempt at a Solution

p = Fmax/A = Fmax/A = 1.1*10^6/(Pi * 0.05^2) = 1.40*10^8 Pa

p=p(not) + ρgd

1.40*10^8 = 101300 + 1030*9.81*d --> d= 13851m

I must be making some sort of error in understanding the theorey of this question. Any help would be greatly appriciated. Thank you kindly.

Kenton