a research submarine has a 20 cm diameter window 8 cm think. the manufacturer says the window van withstand forces up to 1x106N. What is the submarine's maximum safe depth?
p = po + [tex]\rho[/tex]gd
The Attempt at a Solution
p = F/A = 1X106 / 0.03 = 3.2x107 Pa
so now do i use p = po + [tex]\rho[/tex]gd ??
but if i do what would be my [tex]\rho[/tex]?
[tex]\rho[/tex] = m/v = m/[tex]\pi[/tex]r2h
how would i find mass?
thanks in advance for help!