What Is the Maximum Value for the SM Higgs Quartic Coupling?

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SUMMARY

The maximum value for the Standard Model (SM) Higgs quartic coupling, given a Higgs mass of 125 GeV, is calculated using the formula λ = m_h² / (2v²), resulting in approximately 0.1 for v = 246 GeV. Perturbation theory imposes a constraint that λ must remain below 4π, indicating that values exceeding this threshold, such as λ = 10 after loop corrections, invalidate the physical interpretation of the SM Higgs mass. Therefore, while λ can theoretically approach 10, it does not maintain consistency with the established Higgs mass value.

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Monaliza Smile
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Hi all,

I'm little confused about the maximal appropriate value for the SM Higgs quartic coupling and the Higgs mass = 125 GeV. that as ## \lambda =m_h^2 / 2 v^2 \simeq 0.1 ## for ##v = 246 ~ GeV##.

But according to the perturbation theory, ##\lambda ## enters into higher order corrections as ##\lambda/(4 \pi)##. So that the very generic limit from perturbativity constraint is ## \lambda/(4 \pi) < 1 ## or ## \lambda < 4 \pi ##.

Now after loop correction, say ## \lambda = 10 ##, it won't any more account for the SM Higgs mass !

Best.
 
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Monaliza Smile said:
So that the very generic limit from perturbativity constraint

That's not a physical limit. It's a region of validity for a particular calculation.

Monaliza Smile said:
Now after loop correction, say λ=10

But it's not. As you showed earlier, it's two orders of magnitude smaller.
 

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