# What is the maximum value of the current through the inductor?

In your diagram for the initial state, the wire across the bottom connects the negative side of C2 with the negative side of C3. Those two negative plates have some total charge between them. Charge cannot pass through a capacitor, so that total will not change.
Oh yes!!! i had totally forgotten that concept..Thank you so much..Now I will try the sum again and if I get stuck again, i will post my work here so that you can point out my mistake [emoji28]

In your diagram for the initial state, the wire across the bottom connects the negative side of C2 with the negative side of C3. Those two negative plates have some total charge between them. Charge cannot pass through a capacitor, so that total will not change.
I’m so sorry for bothering again because of this one single sum, but could not reach the answer. I hope this os what you meant[emoji1427] #### Attachments

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haruspex
Homework Helper
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I’m so sorry for bothering again because of this one single sum, but could not reach the answer. I hope this os what you meant[emoji1427]View attachment 225600
I'm confused. In the diagram above you have a box showing initial charges as 60, 90, 40. In the circuit itself, taking x as the change in charge, you use 20, 130, 0. In post #17 it was 40, 30, 10.
I can understand that you used x-40 as the change in charge. That would give the x you have at C3 and the 20+x at C1, but not the 130-x at C2. So I think you made a sign error.

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I'm confused. In the diagram above you have a box showing initial charges as 60, 90, 40. In the circuit itself, taking x as the change in charge, you use 20, 130, 0. In post #17 it was 40, 30, 10.
40, 30, 10 are the potential difference applied to charge the capacitros, not the charge itself.

I can understand that you used x-40 as the change in charge. That would give the x you have at C3 and the 20+x at C1, but not the 130-x at C2. So I think you made a sign error.
Initially total charge is 60+90+40 = 190 ?
so charge on capacitor 2 is 190-(20+x +x-40)?
= 190-( 2x-20)
=210-2x
Am I correct now?

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haruspex
Homework Helper
Gold Member
40, 30, 10 are the potential difference applied to charge the capacitros, not the charge itself.

Initially total charge is 60+90+40 = 190 ?
so charge on capacitor 2 is 190-(20+x +x-40)?
= 190-( 2x-20)
=210-2x
Am I correct now?
Whoops... my mistake . Your answer in post #27 was correct.

Whoops... my mistake . Your answer in post #27 was correct.
But answer is not matching. They say its 380/13 for capacitor C3.[emoji27]

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haruspex
Homework Helper
Gold Member
40, 30, 10 are the potential difference applied to charge the capacitros, not the charge itself.
Good point.. but then, for C1, 40*2=?

Good point.. but then, for C1, 40*2=?
i am so sorry, it will be 80 and I have written 60. I am so sorry...I have got the answer now...I have this exam in a week and i dont know what will happen if i do mistakes like this. Thank you sir for your patience and helping me out. And also for reminding me of this concept. Thank you so much.

haruspex