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randomgamernerd

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**Two identical uncharged capacitors A and B each of capacitance C and an inductor L are arranged as shown in the adjacent figure. At t=0, the switch S1 is closed while switch S2 remains open.At time t=t
1. Homework Statement : **

_{o}=√(LC)Π/2, switch S2 is closed and S1 is opened.

After switch S2 is closed and S1 is opened, find the maximum value of current through the inductor.

## Homework Equations

: [/B]Kirchoff’s loop rule,Q=CV for capacitor,

E=-LdI/dt for an inductor

I=I

_{o}sin(wt)

I

_{o}=QW

## The Attempt at a Solution

:[/B]The question also asked to find out charge on capacitor at time t and also current through inductor at that instant. I have successfully found out the charge to be CE and current through inductor to be CE × 1/(√LC).

Now regarding the maximum current through inductor after time t=t

_{o}, i am having problem.

I used Kirchoffs loop rule..

I assumed that charge on capacitor B is x, and that on A is CE-x.

then we have

LdI/dt= (CE-x)/C + x/C.

But then, x/C gets cancelled..

I think I am doing some mistake in assigning charges to the capacitor plates. Please help.