What is the Meaning of the Formula for Bread Pudding?

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Discussion Overview

The discussion revolves around the interpretation of a mathematical formula presented in a blog post, specifically relating to its meaning and context. Participants explore its mathematical significance, potential applications, and its connection to a recipe for bread pudding.

Discussion Character

  • Exploratory
  • Technical explanation
  • Conceptual clarification
  • Debate/contested

Main Points Raised

  • One participant asks for clarification on the formula mentioned in the blog post, seeking its name and further reading.
  • Another participant identifies the formula as a summation, explaining how to evaluate it by substituting integers into the expression.
  • A different participant suggests that the formula relates to the Maclaurin series for cosine, specifically evaluated at \(x = 2\pi\), and references its presence in calculus literature.
  • Some participants humorously note that the formula is actually a recipe for bread pudding, indicating a playful interpretation of the original question.

Areas of Agreement / Disagreement

There is no consensus on the interpretation of the formula; participants present multiple viewpoints, including its mathematical significance and its humorous connection to a recipe. The discussion remains unresolved regarding the primary focus of the formula.

Contextual Notes

Participants express varying levels of familiarity with the mathematical concepts involved, and there are references to both serious mathematical interpretations and lighthearted commentary about the recipe context.

Who May Find This Useful

Readers interested in mathematical series, calculus, or culinary applications of mathematics may find this discussion relevant.

joeyjo100
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It's a sum. For example, [tex]\sum_{k=1}^{n}k=1+2+3+...+n[/tex]

Basically all you do is substitute the first term (shown at the bottom of the summation symbol Sigma) for k into all places where you see k, then you substitute the next integer for all k in the expression and take the sum of them. Do this all the way to infinite, and your final answer will be 1.
 
Do you mean
[tex]\cos(2\pi)=\sum_{k=0}^\infty \frac{(2\pi)^{2k}}{(2k)!}(-1)^k[/tex]
That is the Maclaurin series for cosine. It is in any calculus book. The general case is
[tex]f(x)=\sum_{k=0}^\infty \frac{x^k}{k!}f^{(k)}(0)[/tex]
 
lurf lurf is right. The given formula is the MacLaurin series for cos(x), evaluated at [itex]x= 2\pi[/itex]. And, of course, [itex]cos(2\pi)= 1[/itex].
 
joeyjo100 said:
What does the formula in this blog post mean? What is it called and where can i read more about it?

http://www.askamathematician.com/?p=1284

ey up lad, it's a recipe for bread pudding! doesn't tha know?
 
Alan1000 said:
ey up lad, it's a recipe for bread pudding! doesn't tha know?
Finally, someone giving April first the respect it deserves!
 

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