What is the meaning of 'x R x' and 'x R y --> x R z' in relation notation?

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Homework Help Overview

The discussion revolves around the concepts of reflexivity and transitivity in relation notation, specifically within the context of a set A. Participants explore the meanings of the expressions 'x R x' and 'x R y --> x R z' as they relate to the properties of relations.

Discussion Character

  • Conceptual clarification, Exploratory

Approaches and Questions Raised

  • Participants inquire about the meaning of reflexivity and transitivity, questioning how these properties manifest in specific examples, such as the relation defined by divisibility and the relation defined by 'less than'.

Discussion Status

Some participants have provided examples to illustrate reflexivity and transitivity, while others are seeking clarification on the definitions and implications of these properties. There is an ongoing exploration of whether specific relations meet these criteria.

Contextual Notes

Participants are examining specific relations and their properties, including potential misconceptions about reflexivity and transitivity. The discussion includes attempts to relate these properties to numerical examples and the implications of the definitions provided.

cragar
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Homework Statement


Let R be a relation defined in a set A

If for all [itex]x \in A[/itex] we have x R x, we call R reflexive
what does it mean when they write x R x ?


And
if for all x,y,z in A we have (x R y and y R z) --> x R z, we call R transitive .
I am not sure what they mean by transitive
 
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cragar said:

Homework Statement


Let R be a relation defined in a set A

If for all [itex]x \in A[/itex] we have x R x, we call R reflexive
what does it mean when they write x R x ?


And
if for all x,y,z in A we have (x R y and y R z) --> x R z, we call R transitive .
I am not sure what they mean by transitive

Homework Statement

Let's look at a couple examples. Let A be the natural numbers. Let's define a relation R by saying mRn if m divides n. Let's see if it reflexive and transitive. To check reflexive we need:

For all n in A, nRn, which means n divides n. Obviously true, so this R is reflexive.

To check transitive we need if nRm and mRp then nRp, which in this case means:
If n divides m and m divides p, then n divides p. Can you see that is true so R is transitive.

Now look at a new R defined by mRn means m < n. Can you see this R is not reflexive but it is transitive? Does that help?
 
if m<n then n can't be less than m . so is that why it is not reflexive?
But it is transitive because m<n and there is another # such that m<n<z
 
cragar said:
if m<n then n can't be less than m . so is that why it is not reflexive?
But it is transitive because m<n and there is another # such that m<n<z

That m<n and n<m can't both be true proves it's not SYMMETRIC. It's not REFLEXIVE because n<n isn't true. Do you see how that's related to the x R x?
 
Last edited:
I think i see now, how do we pronounce x R x
and also is this set transitive {(1,2), (2,3) , (1,3 )}
 
Last edited:
cragar said:
I think i see now, how do we pronounce x R x

"x is related by R to x". If R is "less than" than "x is less than x". If R is "divisible" then "x is divisible by x".
 
ok thanks for your response .
I was just wondering if this set I made up was transitive. to check my understanding.
and also is this set transitive {(1,2), (2,3) , (1,3 )}
 
cragar said:
ok thanks for your response .
I was just wondering if this set I made up was transitive. to check my understanding.
and also is this set transitive {(1,2), (2,3) , (1,3 )}

Yes, it is.
 
ok i think i understand now,
 

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