What is the Missing Mean in a Sample of Size 5?

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SUMMARY

The discussion centers on calculating the mean and standard deviation of a sample of size 5, where individual deviations from the mean are provided. The standard deviation is confirmed as 6.782, calculated by squaring the deviations, dividing by n-1, and taking the square root. However, it is established that the mean cannot be determined with the given information, as both the individual values (x1, x2, x3, x4, x5) and the mean itself are unknown.

PREREQUISITES
  • Understanding of basic statistics, including mean and standard deviation
  • Familiarity with the formula for standard deviation (n-1 denominator)
  • Knowledge of sample size implications in statistical calculations
  • Ability to interpret deviation values in relation to a mean
NEXT STEPS
  • Study the properties of the mean and how it relates to sample data
  • Learn about calculating standard deviation in various contexts
  • Explore the implications of missing data in statistical analysis
  • Investigate methods for estimating missing values in datasets
USEFUL FOR

Students preparing for statistics exams, educators teaching statistical concepts, and anyone interested in understanding the limitations of statistical inference with incomplete data.

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Exam is in the next 30 mins so please reply ASAP.
I just need help with this question.

For a sample of size 5, x1 - mean = -5, x2 - mean = 9, x3 - mean = -7, x4 - mean = -2 and x5 - mean = 5
What is standard deviation... answer is 6.782 by squaring all the answers, dividing by n-1 and finding square root.

However, what is the mean of the sample. Is this possible to get missing both x1, x2, x3, x4, x5 and also missing the mean?
 
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However, what is the mean of the sample. Is this possible to get missing both x1, x2, x3, x4, x5 and also missing the mean?

You cannot infer the mean from the information given. NO!
 

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