How Does Sample Size Influence the Variance of the Sample Mean?

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Homework Help Overview

The discussion revolves around the influence of sample size on the variance of the sample mean, particularly in the context of a normal population with a known mean and standard deviation. Participants explore the implications of sample size on the variance and the probability of sample means falling within a specified interval.

Discussion Character

  • Conceptual clarification, Assumption checking, Mathematical reasoning

Approaches and Questions Raised

  • Participants discuss the calculation of the mean and standard deviation for the sampling distribution of the sample mean and the setup of probability statements. Questions arise regarding the nature of variance in samples versus populations, and the effect of averaging observations on variance.

Discussion Status

The conversation is active, with participants questioning the relationship between sample size and variance. Some provide insights into the mathematical foundations of variance in the context of sample means, while others express confusion about the implications of large sample sizes on sample variance and its relationship to population variance.

Contextual Notes

There is an ongoing exploration of assumptions regarding the behavior of sample variance as sample size increases, with references to specific examples such as the heights of newborns. Participants are navigating the nuances of statistical principles without reaching a definitive consensus.

superwolf
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Homework Statement



If all possible samples of size 16 are drawn from a normal population with mean equal to 50 and standard deviation equal to 5, what is the probability that a sample mean \bar{X} will fall in the interval from \mu_\bar{X} - 1.9 \sigma_\bar{X} to \mu_\bar{X}-0.4\sigma_\bar{X}?

2. The attempt at a solution

<br /> Z=\frac{\bar X - \mu}{\sigma /sqrt{n}}<br />
 
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You have all the information you need to

* Calculate the mean and standard deviation for the sampling distribution of \overline X

* Calculate the two endpoints

Find all the numbers I mention above, set up the probability statement, and
finish just as you would for any normal distribution problem.
 
Why is the variance smaller in a sample than in the whole population?
 
It isn't the fact that it is a sample, it is the effect averaging the observations has on the variance of the sample mean.

Remember that if X_1, X_2, \dots, X_n form a random sample from any (not just a normal) distribution that has variance \sigma^2, then for any constants

<br /> \text{Var}[\sum a_i X_i] = \sum a_i^2 \sigma^2 = \sigma^2 \sum a_i^2<br />

In the sample mean a_i = 1/n so, the variance of the sample mean is

<br /> \sigma^2 \sum \frac 1 {n^2} = \sigma^2 \frac{n}{n^2} = \frac{\sigma^2}{n}<br />
 
So if you have a large number of samples, the variance will be zero? Zero variance means that all samples are the same, right?
 
IF you happened to get a sample with all the numbers the same, the sample variance would be zero.

However the variance of the distribution of \overline X will never be zero, unless
1) The original population variance is zero - a highly artificial situation
2) The sample size is infinite - not possible
 
But the sample variance will be very small when the sample size is very large...I still don't understand why. Let's say that I sample the heights of newborn babies, assuming that their heights are normally distributed around 50 cm, and with a standard deviation of 3 cm. If I sample 1000 babies, will the sample variance then be infinitisimal? I would rather expect it to be close to the polulation variance of 3 cm...
 
superwolf said:
But the sample variance will be very small when the sample size is very large...I still don't understand why. Let's say that I sample the heights of newborn babies, assuming that their heights are normally distributed around 50 cm, and with a standard deviation of 3 cm. If I sample 1000 babies, will the sample variance then be infinitisimal? I would rather expect it to be close to the polulation variance of 3 cm...

I'm not sure where the "sample variance will be very small with the sample size is very large" comes from. The sample variance depends only on the numbers in the sample:
a) if the numbers in the sample are all the same, the sample variance will be zero
b) if the numbers in the sample are very nearly equal, the sample variance will be small (close to zero)
c) in general, if the sample size is large, and sampling has been correctly done, we expect the sample variance will be close to the population variance, as in your "baby example"

But the variance of the sample mean,

<br /> \frac {\sigma^2} n<br />

which you calculate when you use the CLT for probability, will be close to zero when
the sample size is large, simply because n occurs in the denominator
 

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