What Is the Molality of a 1.00 M LiBF4 Solution with a Density of 0.852 g/mL?

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Discussion Overview

The discussion revolves around calculating the molality of a 1.00 M lithium tetrafluoroborate (LiBF4) solution with a given density of 0.852 g/mL. The scope includes homework-related problem-solving and mathematical reasoning.

Discussion Character

  • Homework-related, Mathematical reasoning

Main Points Raised

  • One participant seeks assistance in calculating the molality, noting the challenge of having two variables when using density and concentration formulas.
  • Another participant suggests starting with the mass of the solution, asking for the mass of 1 L of the solution and the mass of LiBF4 and the solvent.
  • A participant estimates the mass of the solution to be 852 grams per liter based on the provided density.
  • There is a question posed about whether there are any doubts regarding the calculations.
  • One participant expresses uncertainty about the next steps after estimating the mass.
  • A later reply suggests that reviewing the initial post may clarify the problem further.

Areas of Agreement / Disagreement

Participants do not appear to reach a consensus on the next steps to take in the calculation, and uncertainty remains regarding the approach to find the molality.

Contextual Notes

The discussion lacks clarity on the assumptions made regarding the solution's composition and the definitions of molality and molarity in this context.

geffman1
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Homework Statement


hey guys just wondering how to do this.
Lithium tetrafluoroborate (LiBF4) is sold as a 1.00 M solution in
acetonitrile. If the solution has a density of 0.852 g/mL,
the molality of the solution is?


i tired using denisty=m/v and concentration=n/v but always had 2 variables. any help would be good. thanks
 
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1 L of your solution - what mass? What mass of LiBF4? What mass of solvent?
 
umm, 852 grams/litre?
 
Any doubts?
 
i think it right but don't know what the next step is?
 
Perhaps if you will read my very first post it will become clearer.
 

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