- #1

Benzoate

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## Homework Statement

A 2.02-g sample of an enzyme is used to make a 6.00-mL solution. What is the molar mass of the enzyme if the osmotic pressure of the solution at 298K is 0.123 atm? Note that enzymes are nonelectrolytes

## Homework Equations

pi=MRT , R=.0821 L*atm*K^1-*mol^1-

## The Attempt at a Solution

pi=MRT => pi/RT=M=.123 atm/(298K)(.0821)=.00503 M

to find molar mass, I'd want to convert my concentration into grams/mol

.00503 M =.00503 mmol/1 mL

multiply (.00503 mmol/1mL)*(6.00 mL)= .0302 mmol => .00003016 mol enzyme

so molar mass = 2.02 g enzyme /.00003016 mol enzyme = 66976. 12732 g/mol , which is unusually enormous for a typical molar mass