What is the Molecular Weight of a Gas Using the Ideal Gas Law?

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SUMMARY

The molecular weight (MW) of an unknown gas can be calculated using the Ideal Gas Law formula, PV = nRT. In this discussion, a sample weighing 0.0097561 g occupies 0.2 L at a temperature of 500 K and a pressure of 2 atm. The calculation yields a molecular weight of 1 g/mol, confirming the accuracy of the result. The discussion emphasizes the importance of showing work in calculations to identify potential errors.

PREREQUISITES
  • Understanding of the Ideal Gas Law (PV = nRT)
  • Basic knowledge of units of measurement (grams, liters, atm, Kelvin)
  • Familiarity with molecular weight calculations
  • Proficiency in algebra for manipulating equations
NEXT STEPS
  • Study the Ideal Gas Law in-depth, including its derivations and applications
  • Learn about unit conversions relevant to gas laws, such as converting pressure and volume
  • Explore the concept of molar mass and its significance in chemistry
  • Investigate common errors in gas law calculations and how to avoid them
USEFUL FOR

Chemistry students, educators, and professionals involved in gas analysis or physical chemistry will benefit from this discussion.

gwiber
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1. A 0.0097561 g quantity of an unknown gas occupies 0.2 L at 500 K and 2 atm. What is the Molecular Weight (MW) of the gas ?



2. PV = nRT



3. mw=0.0097561*0.082*500/2*0.2
mw=1
 
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Your answer is right, although it would be nice to see some work shown in case there are any minor errors that could be caught.
 

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