MHB What is the multiplier for finding the area of triangle ADG?

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To find the area of triangle ADG, the area formula A = (bh)/2 is applied, where b represents the base and h the height. The area of triangle CDE is expressed in terms of segments AG and DG, leading to the equation (1/3 AG * 1/3 DG)/2 = 42. To determine the area of triangle ADG, a multiplier must be identified for both sides of the equation. The discussion highlights the challenge of interpreting a small image related to the problem. Ultimately, the focus is on deriving the correct multiplier for calculating the area of triangle ADG.
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Not sure how to use a single area and line segments that are same to calculate the areas and line segments for the areas.
 

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Using the formula for the area, $A$, of a triangle

$$A=\frac{bh}{2}$$

where $b$ is the base of the triangle and $h$ is the height of the triangle, can you state the area of triangle $CDE$ in terms of $AG$ and $DG$?
 
(3)42 = 84/2 so b times h equals 84
 
$$\frac{\frac13AG\cdot\frac13DG}{2}=42$$

Now, what number can we multiply both sides of the above equation by to find $\triangle{ADG}$?
 
greg1313 said:
$$\frac{\frac13AG\cdot\frac13DG}{2}=42$$

Now, what number can we multiply both sides of the above equation by to find $\triangle{ADG}$?

Greg, I'm glad you can read that tiny sideways image, because I sure can't. (Bandit)
 

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