What is the Newtion Ring Experiment?

  • Thread starter Thread starter kenok1216
  • Start date Start date
  • Tags Tags
    Experiment Ring
Click For Summary

Homework Help Overview

The discussion revolves around the Newton Ring Experiment, specifically focusing on the calculation of the distance related to the observed bright rings. Participants are examining the conditions for constructive interference and the implications of refractive indices in the context of the experiment.

Discussion Character

  • Exploratory, Conceptual clarification, Mathematical reasoning, Assumption checking

Approaches and Questions Raised

  • Participants are attempting to derive the relationship between the number of observed rings and the path difference for constructive interference. There are questions regarding the correct conditions for interference and the implications of phase shifts in the context of the refractive indices involved.

Discussion Status

The discussion is ongoing, with participants exploring different interpretations of the path difference conditions for constructive interference. Some have suggested drawing diagrams to clarify the interference conditions, while others are questioning the assumptions made regarding phase shifts and the equations used.

Contextual Notes

There are indications of confusion regarding the application of the formula for path difference and the specific conditions for constructive interference in the context of the experiment. Participants are also referencing textbook material to verify their understanding.

kenok1216
Messages
58
Reaction score
1

Homework Statement


擷取3.PNG

refractive index of prism=1.45
λ=450nm
50 bright ring are observed
find d

Homework Equations


2d=nλ/2

The Attempt at a Solution


since 50 bright rings are observed n=24 (-24---------0-------------24)
if the distance travel=λ/2 constructive interference will happen
since the ray1 reflected by prism(n=1.45--->n=1 air)no phase shift
by ray 2 air to flat plate have phase shift

2d=24(λ/2) and λ=450nm/n=450nm/1.45=310nm
d=[310nm(24)]/4=1.86x10^-6m but the answer=1.11x10^5m why?
[/B]
 
Last edited:
Physics news on Phys.org
kenok1216 said:

Homework Equations


2d=nλ/2
i think
for constructive interference -draw a diagram of the rays interfering at thickness d
the correct condition perhaps is
path difference = n. wavelength (in phase)
and path difference =2.d + (wavelength / 2)
check from your textbook
 
drvrm said:
i think
for constructive interference -draw a diagram of the rays interfering at thickness d
the correct condition perhaps is
path difference = n. wavelength (in phase)
and path difference =2.d + (wavelength / 2)
check from your textbook
so do you mean nλ=2d+
drvrm said:
i think
for constructive interference -draw a diagram of the rays interfering at thickness d
the correct condition perhaps is
path difference = n. wavelength (in phase)
and path difference =2.d + (wavelength / 2)
check from your textbook
why pd=2d+λ/2?
 
kenok1216 said:
so do you mean nλ=2d+

why pd=2d+λ/2?
draw the ray diagram for interference
 

Similar threads

Replies
1
Views
3K
  • · Replies 1 ·
Replies
1
Views
3K
  • · Replies 9 ·
Replies
9
Views
5K
Replies
4
Views
3K
  • · Replies 18 ·
Replies
18
Views
2K
  • · Replies 2 ·
Replies
2
Views
731
  • · Replies 1 ·
Replies
1
Views
813
  • · Replies 1 ·
Replies
1
Views
9K
  • · Replies 11 ·
Replies
11
Views
14K
  • · Replies 3 ·
Replies
3
Views
4K