What is the orbital frequency of an electron and positron 2.00nm apart?

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Homework Help Overview

The discussion revolves around calculating the orbital frequency of an electron and a positron that are 2.00 nm apart. The subject area includes concepts from electromagnetism and circular motion.

Discussion Character

  • Exploratory, Conceptual clarification, Mathematical reasoning

Approaches and Questions Raised

  • Participants discuss treating the electron and positron as a system with torque and explore the application of Newton's laws. Questions arise regarding the correct approach to analyze the forces acting on the particles and the relationship between torque and circular motion.

Discussion Status

Some participants have offered guidance on using Newton's laws and drawing force diagrams. There is an ongoing exploration of the relationship between net force, mass, and circular motion, with no explicit consensus reached yet.

Contextual Notes

Participants note the challenge of determining the angle theta in the torque equation and the need for additional information regarding the forces involved in the circular motion of the particles.

imafam
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A positron is an elementary particle identical to an electron except that its charge is . An electron and a positron can rotate about their center of mass as if they were a dumbbell connected by a massless rod. What is the orbital frequency for an electron and a positron 2.00nm apart?

My Approach:
I treated the electron and positron as a system with a torque.
I found that the torque = pEsintheta = qsEsintheta = (1.60*10^-19)(2*10^-9)(1.94*10^9)
but I don't know theta
HELP!
 
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Hi imafam,

imafam said:
A positron is an elementary particle identical to an electron except that its charge is . An electron and a positron can rotate about their center of mass as if they were a dumbbell connected by a massless rod. What is the orbital frequency for an electron and a positron 2.00nm apart?

My Approach:
I treated the electron and positron as a system with a torque.
I found that the torque = pEsintheta

This is the formula for the torque on a dipole in an external field E, which is not what you have here.

Instead, think in terms of Newton's law. Draw a force diagram for one of the particles. Also, the particles are going in a circular path; what do you know that is true about circular motion, that you can use here in Newton's law Fnet=ma?
 
That Fnet = mv^2/r
alphysicist said:
Hi imafam,



This is the formula for the torque on a dipole in an external field E, which is not what you have here.

Instead, think in terms of Newton's law. Draw a force diagram for one of the particles. Also, the particles are going in a circular path; what do you know that is true about circular motion, that you can use here in Newton's law Fnet=ma?
 
imafam said:
That Fnet = mv^2/r

That's right; once you plug in what Fnet is for this case, you'll have an equation with r and v in it.

From that, you can determine the period of the orbit, which is just how long it takes for the particle to go in a complete circle. And then the frequency is just the reciprocal of the period.
 

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