What Is the Original Concentration of the Solution?

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SUMMARY

The original concentration of a solution can be determined using dilution principles. In this case, a 500 ml solution, when diluted to 2 liters, results in a concentration of 20 g/L. The calculations confirm that the original amount of solute is 40 grams, leading to an original concentration of 40 g in 500 ml, which simplifies to 80 g/L. This conclusion is reached through the application of the dilution formula and understanding of concentration ratios.

PREREQUISITES
  • Understanding of solution concentration and dilution principles
  • Familiarity with basic algebra and ratio calculations
  • Knowledge of units of measurement (grams, liters, milliliters)
  • Ability to manipulate equations involving proportions
NEXT STEPS
  • Study the principles of dilution and concentration in chemistry
  • Learn how to apply the dilution equation: C1V1 = C2V2
  • Explore examples of concentration calculations in various solutions
  • Investigate the effects of temperature and pressure on solution concentration
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Chemistry students, educators, laboratory technicians, and anyone involved in solution preparation and analysis will benefit from this discussion.

DB
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Having a little trouble tackling this one.
"What is the concentration of a 500 ml solution if, when diluted to a volume of 2 Liters, its new concentration becomes 20 g/L?"

Here what I did, all in ml.

\frac{x}{500+1500}

\frac{x}{2000}=\frac{20}{1000}

\frac{20*2000}{1000}=40=x

\frac{40}{2000}=\frac{10}{500}

Obviously the anwser can't be 10g/500ml, can someone help me out?
Thanks
 
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DB said:
\frac{x}{500+1500}

\frac{x}{2000}=\frac{20}{1000}

\frac{20*2000}{1000}=40=x
Right. "x" is the quantity of "stuff" in the mix, in g. That stuff doesn't change when you dilute it, so 40g of stuff must have been in the original 500ml. Now can you calculate the original concentration?
 
O so do you mean that solute is 40g for 2000ml and as well for 500ml? Making the answer 40g/500ml?
 
Yes. That's what I would say.
 
Thanks for all your help :smile:
 

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