What is the Orthonormal Basis of the Plane x - 4y - z = 0?

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SUMMARY

The Orthonormal Basis of the plane defined by the equation x - 4y - z = 0 is derived from two independent vectors. The process begins by identifying vectors that satisfy the equation, specifically (4, 1, 0) and (1, 0, 1). These vectors are then orthogonalized using the Gram-Schmidt process and normalized to yield the final orthonormal basis vectors: e1 = (1/sqrt(2), 0, 1/sqrt(2)) and e2 = (2/3, 1/3, -2/3). The dot product of these vectors confirms their orthogonality.

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  • Familiarity with the Gram-Schmidt orthogonalization process.
  • Knowledge of vector normalization techniques.
  • Basic linear algebra concepts, including dot products and spans.
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I need to find the Orthonormal Basis of this plane:

x - 4y -z = 0

I know the result will be the span of two vectors but I'm not sure where to start. Any hints?

Thanks,

Gab
 
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First find a basis by finding two independent vectors that satisfy that equation. This is easy: find one non-zero vector satisfying that equation with z-component 0, and find another satisfying that equaiton with y-componenet 0. Next, orthogonalize this basis using Gramm-Schmidt. Finally, normalize it by dividing the two orthogonal vectors you have by their own norms.
 
So set (y=1, z=0) and (y=0, z=1)

Get two vectors:

(4,1,0) and (1,0,1)

Normalize:

(4/sqrt(17), 1/sqrt(17), 0) and (1/sqrt(2), 0, 1/sqrt(2))
 
To satisfy the "ortho" part of Orthonormal you need to verify that the dot product of your 2 vectors is 0.
 
Ah thanks,

so e1= (1/sqrt(2), 0, 1/sqrt(2))

e2 = (2/3, 1/3, -2/3)
 

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