What is the output speed at 100 rpm arm rotation in an epicyclic gear box?

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SUMMARY

The output speed of an epicyclic gearbox with an arm rotation of 100 rpm can be calculated by understanding the relationship between the input and output speeds. When the arm is stationary (0 rpm), the output speed is a standard reduction from the input speed. At 300 rpm, the system locks, resulting in the output speed matching the input speed. Therefore, the output speed at 100 rpm arm rotation lies one-third between the output speed at 0 rpm and 300 rpm, providing a definitive output speed calculation.

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Hi,
Cant understand this at all, even modeled the set up with lego but still can't fathom it! I can't see how the arm can rotate with locking something.

Cheers
 

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hi, The diagram is a bit misleading. the output shaft is attached to the second sun gear S2. input is S1, the arm just connects the planetary gears (P1 and P2). Just think about it this way. If you have the arm at 0 rpm, you have just a standard reduction between the input and output right? that's easy to work out, let's call that output X. Now, if you have the arm at 300 rpm, matching the speed of the input, the system will be locked, and the output shaft will be at 300 rpm. extrapolate what you find between these two points to find the output at 100rpm.

Again,
the output will basically lie 1/3rd between the X (arm = 0 rpm) and 300rpm (arm = 300rpm)
 

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