What is the path on the pV diagram for an isobaric expansion from 2 m^3 to 5 m^3?

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SUMMARY

The discussion focuses on the path of an isobaric expansion on a pV diagram, specifically from a volume of 2 m³ to 5 m³. It is established that during an isobaric process, the pressure remains constant, resulting in a horizontal line on the pV diagram. The relevant equations discussed include work done (W = PΔV) and changes in internal energy (ΔU = Q - W). The correct graphical representation is confirmed as a horizontal line parallel to the volume axis, indicating constant pressure throughout the expansion.

PREREQUISITES
  • Understanding of thermodynamic processes, specifically isobaric expansion.
  • Familiarity with the pV diagram and its components.
  • Knowledge of the first law of thermodynamics, including the equations ΔU = Q - W and W = PΔV.
  • Basic grasp of pressure-volume relationships in thermodynamics.
NEXT STEPS
  • Study the implications of isothermal processes on the pV diagram.
  • Learn about the first law of thermodynamics in greater detail.
  • Explore the concept of work done in different thermodynamic processes.
  • Investigate the relationship between pressure, volume, and temperature in ideal gases.
USEFUL FOR

Students and professionals in physics and engineering, particularly those studying thermodynamics and fluid mechanics, will benefit from this discussion.

ApexStudent1
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Draw the path in the pV diagram for an isobaric expansion from a volume of 2 m^3 to 5 m^3.



Idk which of these equations are needed because they all are given with this section...
ΔU=Q-W
ΔU=Q+W
W=PΔV
ΔU=Q
W=nRTln(Vf/Vi)
Q-W
ΔU=-W
ΔU=+W
e=W/Qh=1-Qc/Qh
e=1-Tc/Th
ΔS=Q/T




My attempt...

Graph with x being Volume and y being Pressure, a horizontal line from 2-5
 
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An isobaric expansion means that the pressure is kept constant during the expansion. This means that when you graph the expansion on the pV diagram, you will have a line parallel to the V axis.
So what you did was right...
 

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