What Is the Planck Radiation Formula for Wavelength?

Click For Summary
SUMMARY

The discussion centers on the Planck radiation formula for wavelength, specifically represented as Bf(T)=((2hc²)/(λ⁵))(1/(e^(hc/kT)-1)). This formula, essential in astrophysics, describes the energy distribution emitted by a blackbody at a given temperature. The conversation also details how to reconstruct the frequency version of the formula by substituting variables, demonstrating the relationship between wavelength and frequency in the context of blackbody radiation.

PREREQUISITES
  • Understanding of blackbody radiation principles
  • Familiarity with Planck's constant (h), speed of light (c), and Boltzmann constant (k)
  • Basic knowledge of astrophysics and thermodynamics
  • Ability to manipulate mathematical formulas and variables
NEXT STEPS
  • Study the derivation of the Planck radiation formula for frequency
  • Explore applications of the Planck radiation formula in astrophysics
  • Learn about the significance of blackbody radiation in stellar physics
  • Investigate the historical context of Max Planck's contributions to quantum theory
USEFUL FOR

Astrophysics students, researchers in stellar physics, and anyone interested in the mathematical foundations of blackbody radiation and its applications in understanding stellar behavior.

elessar_telkontar
Messages
16
Reaction score
0
I'm taking a course on astrophysics, and at this time I get the astrophysics of stars. In this section, I have to use the Planck radiation formula, but I have got it for the frecuency of radiation. What's the one for wavelength? I have found one but I tried to reconstruct the one for frecuencies but I can't do it:

The one for wavelength I have found is:

Bf(T)=((2hc2)/(l5))(1/ehc/klT-1)

Please answer me faster that you can.
 
Physics news on Phys.org
elessar_telkontar said:
The one for wavelength I have found is:

Bf(T)=((2hc2)/(l5))(1/ehc/klT-1)

Please answer me faster that you can.

Just substitute:

\lambda=\frac{c}{\nu}

and

d\lambda=-\frac{c}{\nu^2}d\nu

That'll give you the frequency formula.
 
Last edited:


The Planck radiation formula is a fundamental equation in astrophysics that describes the distribution of energy emitted by a blackbody at a given temperature. It was first derived by German physicist Max Planck in 1900 and is essential in understanding the properties and behavior of stars.

The formula you have provided is indeed the Planck radiation formula for wavelength, also known as the spectral radiance. It describes the amount of energy emitted per unit time, per unit area, per unit solid angle, and per unit wavelength interval by a blackbody at a given temperature. This formula is often used to calculate the intensity of radiation emitted by stars at different wavelengths.

To understand the formula, let's break it down into its components. "B" represents the spectral radiance, which is the dependent variable we are trying to calculate. "f" is the frequency of the radiation, "T" is the temperature of the blackbody, "h" is Planck's constant, "c" is the speed of light, "k" is the Boltzmann constant, and "l" is the wavelength.

The first part of the formula, (2hc^2/l^5), represents the spectral radiance of a blackbody at a given temperature and is a constant value. The second part, (1/ehc/kT - 1), is the Planck distribution function, which is used to calculate the probability of a photon having a specific energy at a given temperature. This function takes into account the energy of the photon, the temperature of the blackbody, and the Boltzmann constant.

To reconstruct the formula for frequency, simply replace "l" with "f" and "c" with "l" in the formula you provided. This will give you the Planck radiation formula for frequency:

Bf(T)=((2hf2)/(c5))(1/ehf/kT-1)

I hope this helps you understand the Planck radiation formula better. It is a complex equation, but with practice and understanding, you will be able to use it confidently in your astrophysics studies. Remember to always double-check your calculations and units to ensure accurate results. Best of luck in your course!
 

Similar threads

  • · Replies 3 ·
Replies
3
Views
856
Replies
5
Views
1K
  • · Replies 3 ·
Replies
3
Views
2K
Replies
11
Views
2K
  • · Replies 2 ·
Replies
2
Views
3K
  • · Replies 4 ·
Replies
4
Views
6K
  • · Replies 3 ·
Replies
3
Views
969
Replies
1
Views
2K
  • · Replies 3 ·
Replies
3
Views
2K
  • · Replies 7 ·
Replies
7
Views
2K