What is the polyhedron described by the equation {x} + {y} + {z} = 1

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SUMMARY

The polyhedron described by the equation {x} + {y} + {z} = 1 is a geometric figure formed by the intersection of planes in the three-dimensional space, specifically within the first octant where x, y, and z are non-negative. The analysis reveals that this equation represents a triangular plane in each of the eight octants of the coordinate system. By examining each octant, one can determine the lateral surface area of the polyhedron, which is derived from the vertices formed at the intersections of the axes.

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What is the polyhedron described by the equation {x} + {y} + {z} = 1 ? Justify carefully your answer, and then determine the lateral surface area of this polyhedron.

{x} is modulus of x..

can i know how to do this question ? i can't even understand the question..
 
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Scharles said:
What is the polyhedron described by the equation {x} + {y} + {z} = 1 ? Justify carefully your answer, and then determine the lateral surface area of this polyhedron.

{x} is modulus of x..

can i know how to do this question ? i can't even understand the question..

You know what is modulus of x? It is two things - it is x and it is -x.

Following a 'Polya' strategy, try and solve a simpler related problem, or rather subset of the given problems. Let {z} = 0. Then {x} + { y} = 1. So that is four things but altogether what do they make? Then it should be obvious what the corresponding equations with x and z only and then with y and z only make. Following which it should be obvious what your overall equation represents. Try and find then the simplest way to justify this obvious thing.
 
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Break this into 8 cases- the 8 "octants" of the coordinate system.

For any point in the first octant, x, y, and z are all positive. So |x|= x, |y|= y, |z|= z and |x|+ |y|+ |z|= 1 becomes x+ y+ z= 1. That is a plane. Where does it intersect the axes? Remember that this is only in the first octant.

For any point in the second octant, x< 0 but y and z are still positive. So |x|= -x, |y|= y, |z|= z and |x|+ |y|+ |z|= 1 becomes -x+ y+ z= 1. That is also a plane. Were does it itersect the axes? Remember that this is only in the second octant.

Repeat that analysis for the other six octants.
 

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