What is the potential of the final location of the charge?

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Homework Help Overview

The discussion revolves around the potential of a final location of a charge in an electric field. The original poster describes a scenario involving a +55.0 nC charge initially placed at a potential of 535 V, with the electric field doing 210.0 µJ of work on the charge as it moves.

Discussion Character

  • Exploratory, Assumption checking

Approaches and Questions Raised

  • Participants discuss the use of the equation Va - Vb = -Wba/q to relate work done and potential difference, questioning its applicability given the direction of work done.

Discussion Status

Some participants have provided guidance on clarifying the points involved in the potential calculation. There is an ongoing exploration of how to correctly apply the work-energy principle in this context, with no explicit consensus reached yet.

Contextual Notes

There is a mention of confusion regarding the points A and B in the context of the potential and work done, which may affect the understanding of the problem setup.

NegaChin
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There is an E-field in a region of space, and a +55.0 nC charge is placed at a point where the potential is 535 V. When released the charge moves, while the field does 210.0 µJ of work on it. What is the potential of the final location of the charge?
 
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Again, please show what you have tried so far and explain where you are stuck.
 
I have tried the equation Va - Vb = -Wba/q, where Va is the potential at point A and Vb is the potential at point B. This equation was from a textbook, however, I later realized that it was only going to find the work done to move the object from point B to point A. Since the problem gives me the work done from point A to B, I am stuck.
 
Point A is the point with the 535 V potential, in case you were confused.
 

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