What is the power of the engine in a moving elevator?

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SUMMARY

The discussion focuses on calculating the power used by an elevator engine under two scenarios: moving upward at a constant speed of 2 m/s and accelerating from rest at 0.75 m/s². For the first scenario, with an engine efficiency of 90% and a lift mass of 950 kg, the power used is determined to be 19,000 W. In the second scenario, the discussion involves analyzing the forces acting on a physics student in an elevator, where the scale readings change based on the elevator's acceleration, leading to calculations of force and power. Key distinctions between power and force are emphasized, highlighting the importance of understanding these concepts in physics.

PREREQUISITES
  • Understanding of Newton's laws of motion
  • Basic knowledge of power calculations in physics
  • Familiarity with the concepts of force and weight
  • Ability to perform calculations involving mass, acceleration, and efficiency
NEXT STEPS
  • Study the relationship between power, work, and energy in physics
  • Learn about the implications of elevator dynamics on force and acceleration
  • Explore the concept of mechanical efficiency in engineering applications
  • Investigate the effects of varying mass and acceleration on scale readings in elevators
USEFUL FOR

Students studying physics, particularly those focusing on mechanics, as well as engineers and professionals involved in elevator design and safety assessments.

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Homework Statement



1.Lets look at the motion of a lift in two situations:a) The lift moves upward with a constant speed of 2m/s.how much electrical power goes the engine of the llift use if the efficiency of the engine is 90% ?
b) Whats the power at time 1.5s when the lift started upwards from rest at time zero with accceleration 0.75 m/s² ? we assume that there are no counterweghts so the engine has to lift the whole mass of the lift which is 950kg. (PS ineed the reply ASP THANKS for the help)

Homework Equations



This is the second question!
question (2)
2.A physics student stands in an elevator on a bathroom scale. when the elevator is at rest the scale gives a reading of 560N. as the elevator starts moving, the scale reads 800N. a) Find the acceleration of the elevator (direction and magnitude). b) what is the acceleration if the scale reads 450N? c) if the scale reads zero, should the student worry? explain.(PS ineed the reply ASP THANKS for the help)

The Attempt at a Solution


solution1

F=W = mg = 950*10= 9500N
F-W=ma msince a = 0 then F=W
Pused = 0.9*Pin
Pused = 9500* 2 = 19000Pin = 10/9*Pused

soulation2
F =ma
w=mg= 560N
w-f = 800N
mg-ma =800N
ma= mg -800N
= 560-800N
=-240N
 
Last edited:
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I understand that in the everyday language you can interchange the words power and force.
However this is not so in physics. Power is not the same thing as Force.
You did calculate the force correctly. Now calculate the power. Look up the definition if you did not do it yet. (It is related to work).
 

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