(adsbygoogle = window.adsbygoogle || []).push({}); 1. The problem statement, all variables and given/known data

A 650kg elevator starts from rest. It moves upward for 3s with constant acceleration until it reaches its cruising speed of 1.75m/s.

A) What is the average power of the elevator motor during this time period?

B) How does this power compare with the motor power when the elevator is at its cruising speed?

2. Relevant equations

I think I did part a correctly, but I would like someone to check it. I don't really understand where to start with part b, how is it different than part a?

3. The attempt at a solution

Pavg = W/dT = (F*d)/t = ((ma+mg)*(v*t))/t = ((m(v/t)+mg)*(v*t))/t = (650kg(((1.75m/s)/3s) + 9.8m/s^2)*(1.75m/s*3s))/3s = 11811.04W

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# Homework Help: Finding the power of an elevator motor

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