What is the predicted distribution of modification states in antibodies?

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The discussion focuses on the predicted distribution of modification states in antibodies, specifically analyzing the probabilities of different modification configurations. The calculations indicate that the probability of having no modifications (00) is 64%, one modification (0+) is 32%, and two modifications (++) is 4%. The user employs a probabilistic approach using the formulas prob(+) = 0.2 and prob(0) = 0.8, correctly accounting for degeneracy in the distribution. The user seeks clarification on the statistical description of these results and the underlying logic.

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Antibodies are large proteins with 2 equal halves. After analysis in which we break apart the two halves, we find we have a modification at one location on 20% of the total protein. For the intact antibody, this modification can occur on both halves (2 per antibody) or only on one half (1 per antibody). If 0 = a half with no modification and + = a half with the modification, then what is the predicted distribution (% of total whole antibody) of the three modification states, 00, 0+, and ++? Our N is in moles (10 to the 23rd power) and therefore, assuming the 1st modification doesn't affect the 2nd occurring on the same antibody, I should be able to derive an almost exact result.

I have been using prob(+) = 0.2 and prob(0) = (1 - prob(+)) = 0.8, so
prob(00) = (0.8)*(0.8) = 0.64
prob(0,+) = (0.8)*(0.2) = 0.16 (*2 degeneracy = 0.32)
and prob(+,+) = (0.2)*(0.2) = 0.04

Am I correct? If so, what is the proper statistical description (i.e. fundamental distribution formula I can refer to)? If not, correct me please. I am not able to statistically explain (in a formula) the degeneracy (instead resorted to Mendel and basic genetics). I am hoping I am pretty close but would like to fill the logic gaps so I can explain properly to others.
 
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You are correct. The x 2 factor results from counting +- and -+ as the same.
 

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