What is the present age of the mother and son in this age problem?

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The present age problem establishes that a mother is currently 30 years old, while her son is 3 years old. The relationship is defined by the equation where the mother is 10 times the son's age. In six years, the mother will be 36, and the son will be 9, confirming that she will then be four times his age. The calculations demonstrate the validity of these age relationships through algebraic manipulation.

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A mother is 10 times as old as her son. In six years time she will be four times as old as her son. Find the present age of the mother.

Here is the set up:

Mother = 10x

Son = x

10x + 6 = 4(x + 6)

Correct?
 
Last edited:
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Complete the problem and check your work to find out! :)
 
10x + 6 = 4(x + 6)

10x + 6 = 4x + 24

10x - 4x = 24 - 6

6x = 18

x = 18/6

x = 3

So, the son is 3 and his mom is 30.
 
Last edited:
RTCNTC said:
A mother is 10 times as old as her son. In six years time she will be four times as old as her son. Find the present age of the mother.

Here is the set up:

Mother = 6x

Son = x

6x + 6 = 4(x + 6)

Correct?

?

try again ...
 
skeeter said:
?

try again ...

I corrected my typo.
 

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