What is the quickest way to refresh my memory on quadratic equations?

AI Thread Summary
To quickly refresh memory on quadratic equations, understanding the formula (x+a)^2 = x^2 + 2ax + a^2 is essential. The discussion highlights the importance of the FOIL method for expanding binomials, illustrated with examples like (x+5)^2. Users share tips on how to visualize and calculate these equations, emphasizing practice and organization of notes. The conversation also reflects a sense of community support, with participants helping each other grasp the concepts. Overall, a solid grasp of these fundamentals is crucial for successfully completing related projects.
frankensteak
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i learned this a few weeks ago and now i have a project due tomorrow and i want to make sure in doing this right before i make useless graphs...

like: (x-1)^2+3

or (x+2)^2

i can't remember how to exponent that ****...
 
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(x+a)^2=x^2+2xa+a^2

Was it the question that you were asking that was cencored? Or are you asking how to graph the functions?
 
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how did you do that
 
im asking..

how to (x+5)squared
 
Think of it this way.

12^2 =(10+2)*(10+2)=10*10+10*2+2*10+2*2=100+20+20+4=144
(x+a)^2=(x+a)*(x+a) =x*x+x*a+x*a+a*a=x^2+2xa+a^2

Are you familiear with FOIL?

(x+5)^2 (a=5)=x^2+2ax+a^2=x^2+2*5*x+5^2=x^2+10x+25
 
no.. i get it..

i tried to find my notes but organization isn't really my thing..
but i got it now, thanks to you! :D

mucho grassy ass
 
Seemingly by some mathematical coincidence, a hexagon of sides 2,2,7,7, 11, and 11 can be inscribed in a circle of radius 7. The other day I saw a math problem on line, which they said came from a Polish Olympiad, where you compute the length x of the 3rd side which is the same as the radius, so that the sides of length 2,x, and 11 are inscribed on the arc of a semi-circle. The law of cosines applied twice gives the answer for x of exactly 7, but the arithmetic is so complex that the...

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