The discussion revolves around calculating the range of a soccer player's kick, where the player kicks a stationary ball at a speed of 20 m/s at an angle of 15 degrees to the horizontal. The problem involves concepts from projectile motion, including initial velocity components and the effects of gravity.
The discussion is active, with participants exploring different aspects of the problem, including the calculation of vertical speed and the time to reach maximum height. Some guidance has been offered regarding the horizontal motion and the absence of horizontal acceleration, but there is no explicit consensus on the correct approach or final answer.
Participants are working under the constraints of homework rules, which may limit the information they can use or the methods they can apply. There is also uncertainty about the correct interpretation of the initial velocity components and how to apply them in the context of the problem.
yellow_angel said:mmm... so i calculate the vertical speed: 20sin15=5.18m/s? and with that i can find at what time it reaches the max height by doing V=Vo+at: V=5,18/9.8= 0.53s do i have to multiply the time by 2 and then do the same thing to find the horizontal range?
X=Xo+volt-1/2gt(square) where g=0 and Xo=0 too, so it would be X=19.32*(2*0.53s)?
Correct, there is no horizontal force, so no aceleration, so speed is constantyellow_angel said:hmm...the only force i see is the Vx=20m/s cos 15=19.32m/s it's the only one horizontaly